*Post by Laurence Reeves**Post by Peter Hendriks*Good morning from cold Ruurlo.

This time my new puzzle is a minimax problem. Try to fit three triangles in

a smallest possible square. But choose the triangles in such a way that the

square is as large as possible. Sounds sort of contradictory, uh?

To be honest, I have no idea if this puzzle is simple or difficult. But, in

either case, hopefully it will give you some pleasure.

Good luck!

Peter

http://home.planet.nl/~p.j.hendriks/ppvdw.htm

Please answer by email and not in this newsgroup.

Triangle A) 3,4,5

Triangle B) 5,12,13

Triangle C) 0,Inf,Inf

I win!

:->

I'm not sure that last one qualifies as a triangle, looks like a line to me. I

was going to go with one side being 1, the other sides being Graham's number.

Anyways, if Peter is going to post the link, then well and good, we can all

follow it. But on the other hand if he posts a description of the puzzle, he may

as well post it correctly:

========================================================

The title sounds as a contradiction, but I will try to explain. Here you see

three triangles inside a square. The triangles do not overlap. Although the

triangles are stuck in the square, This square is not the smallest square

possible in which the three triangles fit. After some rearranging you will

easily find a smaller square.

I give you nine line segments with lengths 3, 5, 7, 11, 13, 17, 19, 23 and 29 cm

respectively. You will immediately recognize the first nine odd primes.

The puzzle is to combine the nine segments into three triangles, such that the

smallest possible square, in which these triangles fit, is as large as possible.

What size is this largest smallest square?

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--

Patrick Hamlyn posting from Perth, Western Australia

Windsurfing capital of the Southern Hemisphere

Moderator: polyforms group (polyforms-***@egroups.com)