j***@gmail.com
2014-12-08 10:37:15 UTC
4xy dx + (x^2+1)dy = 0
x^2+1) dy = - 4xy dx
1/2x *(x^2+1) dx = -2ydy
2*ln|x| *(x^2+1)^2 dx = -y^2+c
y^2 + 2*ln|x|*(x^2+1)^2= c
book answer: (x^2+1)^2 y=c
JPD
x^2+1) dy = - 4xy dx
1/2x *(x^2+1) dx = -2ydy
2*ln|x| *(x^2+1)^2 dx = -y^2+c
y^2 + 2*ln|x|*(x^2+1)^2= c
book answer: (x^2+1)^2 y=c
JPD